(4y-1)(2y+7)=8y^2-15y+6

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Solution for (4y-1)(2y+7)=8y^2-15y+6 equation: 



(4y-1)(2y+7)=8y^2-15y+6

We move all terms to the left:

(4y-1)(2y+7)-(8y^2-15y+6)=0

We get rid of parentheses

-8y^2+(4y-1)(2y+7)+15y-6=0

We multiply parentheses ..

-8y^2+(+8y^2+28y-2y-7)+15y-6=0

We get rid of parentheses

-8y^2+8y^2+28y-2y+15y-7-6=0

We add all the numbers together, and all the variables

41y-13=0

We move all terms containing y to the left, all other terms to the right

41y=13

y=13/41

y=13/41

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